a boutique handmade umbrella factory currently sells 22500 umbrellas per year at a cost of 9 dollars each. in the previous year when they raised the price to 16 dollars, they only sold 12000 umbrellas that year. assuming the amount of umbrellas sold is in a linear relationship with the cost, what is the maximum revenue?

Answer:The revenue will be maximum when the price of each umbrella will be $12.Step-by-step explanation:Let the number of umbrellas sold n(c) is a linear function of the cost of each umbrella (c, say). And the relation is n(c) = xc + y ......... (1) Now, at c = 9 dollars, n(9) = 22500 and at c = 16 dollars, n(16) = 12000 Hence, from the equation (1) we get  22500 = 9x + y ........ (2) and  12000 = 16x + y .......... (3) Hence, from equations (2) and (3) we get (16x - 9x) = -10500 ⇒ 7x = -10500 ⇒ x = -1500 Now, from equation (2), we get 22500 = 9 × (-1500) + y ⇒ y = 36000 Therefore, the relation is n(c) = - 1500c + 36000 Now, the revenue will be given by R = n(c) × c =  - 1500c² + 36000c Condition for maximum revenue is [tex]\frac{dR}{dc} = 0 = -3000c + 36000[/tex] ⇒ c = 12 dollars. Therefore, the revenue will be maximum when the price of each umbrella will be $12. (Answer)