Solve the system algebraically check your work 2x+Y- 10=0;X-y-5=0

Answer: x = 5 and y = 0 is correct solution of 2x + y -10 = 0 and x – y – 5 =0 Solution: Two given equations which needs to be solve are  2x + y – 10 = 0    ------ (1) x– y – 5 = 0       ------ (2)  Let’s modify equation (1) 2x + y – 10 = 0     y =10 - 2x        ------ (3) On substituting value of y from equation (3) in equation (2) we get x – (10 – 2x) -5 = 0 x – 10 + 2x – 5 = 0 3x -15 = 0 x = 5 Substituting x = 5 in equation (3) to get value of y. y = 10 – 2 [tex]\times[/tex] 5 = 10 – 10 = 0 So on solving given equation we get x = 5 and y = 0. Lets substitute value of x = 5 and y = 0 in equation (1) and equation (2) to check whether these calculated values satisfies given equations or not. For equation (1), 2 [tex]\times[/tex] 5 + 0 – 10 = 10 – 10 = 0 For equation (2), 5 – 0 – 5 = 0  On solving, in both cases LHS = RHS for calculated values of x = 5 and y = 0. Hence x = 5 and y = 0 is correct solution of two given equation.